Question

In ΔABC, If a = 2 cm, b = 3 cm, c = 4 cm, then find cos A.

Answer 1

Answer:

The required answer is " cosA= 21/24 "

Explanation:

Given that

a = 2 cm, b = 3 cm, c = 4 cm

We know that

$cosA=\frac{b^{2}+c^{2}-a^{2}}{2bc}\\ \\cosA=\frac{3^{2}+4^{2}-2^{2}}{2(3)(4)}\\\\cosA=\frac{9+16-4}{24}\\\\cosA=\frac{9+16-4}{24}\\\\cosA=\frac{21}{24}$

Hope it will help You.

Answer 2

Answer:

hope it helps you .

sorry if it is wrong.