In ∆ABC if ∠A = 2x°, ∠B = 3x° and ∠c = 4x° then find ∠A and ∠C
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Answered by
4
Answer:
A=40° and C=80°
Step-by-step explanation:
A+B+C = 180° [sum of angles of a triangle is 180°]
or, 2x°+3x°+4x° = 180°
or, 9x° = 180°
or, x = 180°/9°
•°• x = 20°
Now,
A = 2x° = 2×20° = 40°
C = 4x° = 4×20° = 80°
Answered by
5
Solution :-
Given ,
- ∠A = 2x°
- ∠B = 3x°
- ∠C = 4x°
We need to find ,
- ∠A & ∠C
Using angle sum property of triangle
→ ∠A + ∠B + ∠C = 180°
→ 2x° + 3x° + 4x° = 180°
→ 9x° = 180°
→ x° = 180°/9
→ x = 20°
Now substituting the value of x in ∠A = 2x° & ∠C = 4x°
• ∠A = 2x° = 2 ( 20° ) = 40°
• ∠C = 4x° = 4 ( 20° ) = 80°
Hence , ∠A = 40° & ∠C = 80° .
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