Math, asked by arpatelzoya9366, 11 months ago

In Δ ABC, if ∠A=40° and ∠B=60°. Determine the longest and shortest sides of the triangle.

Answers

Answered by gauravbindal29
0

Answer:

Longest = AB

Shortest = BC

Step-by-step explanation:

angle a+angle b+angle c=180

40+60+c =180

100+c =180

C =180-100

=80

Angle C =80

Longest=AB

Shortest=BC

(Side opposite to longer angle is longer)

Answered by nikitasingh79
0

Given: In Δ ABC, ∠A = 40° and ∠B = 60°.  

We know that, the sum of all angles of triangle is 180°.

∠ A + ∠ B + ∠ C = 180°

40° + 60° + ∠ C = 180°

∠ C = 180° – 100° = 80°

∠ C = 80°

Now, 40° < 60° < 80°

∠ A < ∠ B < ∠ C

Since the side opposite to the greatest angle is largest. Therefore , side opposite to  ∠ C i.e AB is largest.

Since the side opposite to the smallest angle is the smallest. Therefore , side opposite to  ∠ A i.e BC is Smallest.

Therefore, BC < AC < AB

Hence, AB is longest and BC is shortest side.

HOPE THIS ANSWER WILL HELP YOU…..

 

Similar questions :

In Δ ABC, side AB is produced to D so that BD=BC. If ∠B=60° and ∠A=70°, prove that:

(i) AD > CD (ii) AD > AC

https://brainly.in/question/15907748

 

In a Δ ABC, if ∠B=∠C =45°, which is the longest side?

https://brainly.in/question/15907755

 

Similar questions