Question

In ABC, if A + B = 125° and B + C = 130°, find A, B and C.
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Answer 1

Step-by-step explanation:

A+B =125

B +C = 130

A-C = -5

A+B+C = 180

125+A+5 = 180

A+130 =180

A = 50

50+B= 125

B = 75

75+C = 130

C = 55

Answer 2

Answer:

A=50°; B= 75°; C= 55°

Step-by-step explanation:

We know that- A+B+C=180°

A+B=A+B+C-C=180°-C

A+B=125° (Given)

Hence, 180°-C=125°- Eq1

By solving Eq1, C=180°-125°=55°

B+C=A+B+C-A=180°-A

B+C=130° (Given)

Hence, 180°-A=130°- Eq2

By solving Eq2, A= 180°-130°=50°

B=180°-(55°+50°) =180°-105°=75°

Hence, solution and the explanation are provided by the angle sum property of a triangle.

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