In ∆ABC, if A=B/2=C/3, find A,B,C
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A+B+C=180
A+2A+3A=180
6A=180
A=30
B=2×30=60
C=3×30=90
A+2A+3A=180
6A=180
A=30
B=2×30=60
C=3×30=90
sauravkumar429:
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