Math, asked by yashikamota, 3 months ago

In ∆ABC If ∆A:∆B:∆C =2:5:2then find all the angels of ∆ABC​

Answers

Answered by prathima2406
1

Answer:

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Answered by baijumathew75
5

Answer:

let the unknown number be x

Step-by-step explanation:

the unknown number be x

A=2x

B=5x

C=2x

A+B+C = 180'( angle sum property of a triangle)

so,

2x+5x+2x=180'

7x=180

x=180÷7

x= 25.7

angle A = 2 × 25.7 =51.4

angle C = 51.4

angle B= 5×25.7=128.5

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