In ∆ABC If ∆A:∆B:∆C =2:5:2then find all the angels of ∆ABC
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let the unknown number be x
Step-by-step explanation:
the unknown number be x
A=2x
B=5x
C=2x
A+B+C = 180'( angle sum property of a triangle)
so,
2x+5x+2x=180'
7x=180
x=180÷7
x= 25.7
angle A = 2 × 25.7 =51.4
angle C = 51.4
angle B= 5×25.7=128.5
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