Question

in∆abc if ab =12cm and a perpendicular d is drawn from a at BC,so that angle DAC=50° and angle ABD=60°,the find the area of that triangle.
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Answer 1

Answer:

Solution



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We know that if a line through one of the vertex of a triangle divides the opposite side in the ratio of the other two sides, the line bisects the angle at the vertex.

So in the given equation,

ACAB=CDBD

⇒AD bisects ∠A.

∠A=180∘−(70∘+50∘)   (Sum of angles of a triangle =180∘)

∴∠BAD=2∠A=260∘=30∘

Step-by-step explanation:

hope it helps

Answer 2

Step-by-step explanation:

We know that if a line through one of the vertex of a triangle divides the opposite side in the ratio of the other two sides, the line bisects the angle at the vertex.

So in the given equation,

ACAB=CDBD

→ AD bisects ZA.

ZA=180°-(700+50°) (Sum of angles of a

triangle =180°)

..<BAD=2<A=260⁰=30°