Question

In ∆ABC if AB = AC and ∠B = 500, ∠C =?​

Answer 1

Answer:

Given, AB=AC and ∠B=50

o

We have to find ∠A

As ∠B=50

o

, we have ∠C=50

o

Therefore, ∠A+∠B+∠C=180

o

⇒50+50+∠A=180

o

⇒100+∠A=180

o

⇒∠A=80

o

Step-by-step explanation:

HOPE U LIKE IT

Answer 2

Answer

I think your question is "In ∆ABC if AB = AC and ∠B = 50°, ∠C =?​"

If ABC is triangle with two equal sides, then it is a isosceles triangle.

As you know that in a isosceles tringle two angles are also equal,

Let the ∠A and ∠B are equal, then ∠A will be equal to 50° because ∠A is equal to ∠B

Sum of all angles of a triangle is 180°

Then two ∠A and ∠B are 50° each.

180° = ∠A+∠B+∠C

180° = 100+∠C

∠C = 180-100 = 80°

Hence, ∠C is equal to 80°