In ΔABC,if AB=AC and ∠CAD is an exterior angle.If ∠CAD=70,then find the angles of ABC.(mention proper steps)
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Step-by-step explanation:
AC = AD and AB being the bisector of ∠A. Now, in ΔABC and ΔABD, AC = AD[Given] AB = AB[Common]∠CAB = ∠DAB [∴ AB bisects ∠CAD] ∴ Using SAS criteria, we have ΔABC ≌ ΔABD. ∴ Corresponding parts of congruent triangles (c.p.c.t) are equal. ∴ BC = BD.
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