In ΔABC,if AB=AC and ∠CAD is an exterior angle.If ∠CAD=70,then find the angles of ABC.(mention proper steps)
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Answer: ABC = 35° ACB=35° BAC = 110°
Step-by-step explanation:
|_ CAD +|_ CAB = 180° (Linear pair)
70° + |_ CAB = 180°
|_ CAB = 180° - 70°
|_ CAB = 110°
Given that AB = AC
So, |_ ABC = |_ ACB
Now,
|_ ABC + |_ ACB + |_ BAC = 180° (Angle Sum Property)
2|_ ABC +|_ CAB = 180°
2|_ ABC + 110° = 180°
2|_ ABC = 180 - 110
2|_ ABC = 70°
|_ ABC = 70/2
|_ ABC = 35° = |_BAC
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