Question

In ∆ABC,if AB²=AC²+CB².state with reason whether ∆ABC is a right angled triangle or not ❌.​

Answer 1

$\underline{\textsf{Given:}}$

$\textsf{In triangle ABC,}$

$\mathsf{AB^2=AC^2+BC^2}$

$\underline{\textsf{To find:}}$

$\textsf{Whether triangle ABC is right angled or not}$

$\underline{\textsf{Solution:}}$

$\underline{\textsf{Converse of Pythagoras theorem:}}$

$\textsf{If square of one side of a triangle is equal to sum of the}$

$\textsf{squares of the other two sides, then the angle contained}$

$\textsf{by the two sides is right angle.}$

$\textsf{Consider,}$

$\mathsf{AB^2=AC^2+BC^2}$

$\textsf{According to converse of Pythagoras theorem,}$

$\mathsf{{\triangle}ABC}\;\textsf{is right angled}$

Answer 2

Answer:

yes it is right angle triangle by converse of Pythagoras theorem

Step-by-step explanation:

Given :

AB²=AC²+CB²

to find :

weather the ΔABC is right angle triangle

solution :

if a square of one side is the sum of the two other sides then the triangle is right angle triangle

therefore by converse of Pythagoras theorem

ΔABC is right angle triangle