Question

In ∆ABC,If AB2=AC2+CB2,State with reason whether∆ABC is a right angled Triangle or not​

Answer 1

Step-by-step explanation:

Given:

\textsf{In triangle ABC,}In triangle ABC,

\mathsf{AB^2=AC^2+BC^2}AB

2

=AC

2

+BC

2

\underline{\textsf{To find:}}

To find:

\textsf{Whether triangle ABC is right angled or not}Whether triangle ABC is right angled or not

\underline{\textsf{Solution:}}

Solution:

\underline{\textsf{Converse of Pythagoras theorem:}}

Converse of Pythagoras theorem:

\textsf{If square of one side of a triangle is equal to sum of the}If square of one side of a triangle is equal to sum of the

\textsf{squares of the other two sides, then the angle contained}squares of the other two sides, then the angle contained

\textsf{by the two sides is right angle.}by the two sides is right angle.

\textsf{Consider,}Consider,

\mathsf{AB^2=AC^2+BC^2}AB

2

=AC

2

+BC

2

\textsf{According to converse of Pythagoras theorem,}According to converse of Pythagoras theorem,

\mathsf{{\triangle}ABC}\;\textsf{is right angled}△ABCis right angled

Answer 2

$\rm\underline\bold{Question \purple{\huge{\checkmark}}}$

In ∆ABC,If AB2=AC2+CB2,State with reason whether∆ABC is a right angled Triangle or not

$\huge{\tt{\colorbox{orange}{AnswEr:}}}$

Given:

In triangle ABC,

AB? = AC? + BC?

To find:

Whether triangle ABC is right angled or not

Solution:

Converse of Pythagoras theorem:

If square of one side of a triangle is equal to sum of the squares of the other two sides, then the angle contained by the two sides is right angle.

Consider,

AB? = AC? + BC?

According to converse of Pythagoras theorem,

AABC is right angled