Question

In ABC, if ABP-ACCB", state with reason whether ABC as a night
angled triangle or not​

Answer 1

We know that

a

2

+b

2

=p

2

AB

.

AC

+

BC

.

BA

+

AC

.

CB

=0

CA

.

CB

=0

AB

⊥

AC

∣

∣

∣

∣

AB

∣

∣

∣

∣

∣

∣

∣

∣

AC

∣

∣

∣

∣

cosθ+

∣

∣

∣

∣

BC

∣

∣

∣

∣

∣

∣

∣

∣

BA

∣

∣

∣

∣

cos(90−θ)+0

pbcosθ+apcos(90−θ)

pbcosθ+apsinθ

p(bcosθ+asinθ)

p(pcosθcosθ+psinθsinθ)

=p

2