Question

In ABC, if AD divides BC in the ratio m : n, then find the ratio of the areas of ABD & ADC.

Answer 1

Answer:

AD divides BC in the ratio m:n, then

BD=mx and DC=nx

Area of △ABD=21×AD×BD=21AD×mx

Similarly, area of △ADC=21AD×nx

Thus, ar(△ACD)ar(△ABD)=nm

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