In ABC ; if AD is the median;then show that AB^2+AC^2=2(AD^2+BD^2)
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to prove AB^2 + BC^2 =2(AD^2 + BD^2)
PROOF
in triangle ABD
AD^2 + BD ^2 =AB^2...................1
in triangle ADC
AD^2 + DC ^2 =AC^2..................2
ADD 1,2
AB^2 =AD^2+ DC^2
BC^2 = AD^2+ BD^2
AB^2 + BC^2 =2(AD^2 + BD^2)
PROOF
in triangle ABD
AD^2 + BD ^2 =AB^2...................1
in triangle ADC
AD^2 + DC ^2 =AC^2..................2
ADD 1,2
AB^2 =AD^2+ DC^2
BC^2 = AD^2+ BD^2
AB^2 + BC^2 =2(AD^2 + BD^2)
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akumaien3:
But we don't know if median is perpendicular so how can we apply Pythagorean theorem
Wrong prove
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0
Answer:
Step-by-step explanation:
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