Question

in ∆ ABC, if angle 1=angle 2, prove that AB/AC=BD/DC.​

Answer 1

SOLUTION

Given: A ΔABC in which ∠1 = ∠2

To prove:

AB

AC

=

BD

DC

ABAC=BDDC

Construction: Draw CE || DA to meet BA produced in E.

Proof: since, CE || DA and AC cuts them.

∴ ∠2 − ∠3 …. (i) [Alternate angles]

And, ∠1 − ∠4 ….(ii) [Corresponding angles]

But, ∠1 − ∠2 [Given]

From (i) and (ii), we get

∠3 − ∠4

Thus, in ΔACE, we have

∠3 = ∠4

⇒ AE = AC … (iii) [Sides opposite to equal angles are equal]

Now, In ΔBCE, we have

DA || CE

⇒

BD

DC

=

BA

AE

⇒BDDC=BAAE [Using basic proportionality theorem]

⇒

BD

DC

=

AB

AC

⇒BDDC=ABAC [∵ BA – AB and AE – AC from (iii)]

Hence,

AB

AC

=

BD

DC

ABAC=BDDC