In ∆ ABC if angle A=2x+5, angle B=3x-5 and angle C= 80°.then find the value of x, Angle A and Angle B.
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Answer:
x = 20,
∠A = 45°
∠B = 55°
Step-by-step explanation:
∠A=2x+5,
∠B=3x-5,
∠C= 80°
∵ angle sum of any triangle=180°
∴ ∠A+∠B+∠C = 180°
⇒2x+5+3x-5+80° = 180°
⇒ 5x+80 = 180°
⇒ 5x= 180-80
⇒ x=100/5
⇒ x=20
∴ ∠A : 2x+5=2(20)+5=40+5=45°
∴ ∠B : 3x-5=3(20)-5=60-5=55°
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