Math, asked by poojabhandari4779, 6 months ago

In ∆ ABC if angle A=2x+5, angle B=3x-5 and angle C= 80°.then find the value of x, Angle A and Angle B.

Answers

Answered by cheshtakabra12399
2

Answer:

x = 20,

∠A = 45°

∠B = 55°

Step-by-step explanation:

∠A=2x+5,

∠B=3x-5,

∠C= 80°

angle sum of any triangle=180°

∴ ∠A+∠B+∠C = 180°

⇒2x+5+3x-5+80° = 180°

⇒ 5x+80 = 180°

⇒ 5x= 180-80

⇒ x=100/5

x=20

∴ ∠A : 2x+5=2(20)+5=40+5=45°

∴ ∠B : 3x-5=3(20)-5=60-5=55°

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