In ∆ABC ,If Angle A+Angle B=120⁰,Angle C+Angle A=125⁰ then Find the value of Angle A
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Step-by-step explanation:
Given,
/_A + /_B = 125°
/_A + /_C = 113°
Now,
The angle sum property of triangle,
/_A + /_B + /_C = 180°
125 + /_C = 180
/_C = 180 - 125
/_C = 55°
And,
/_A + /_B + /_C = 180°
/_B + 113 = 180
/_B = 180 - 113
/_B = 67°
Again,
/_A + /_B + /_C = 180°
/_A + 67 + 55 = 180
/_A + 122 = 180
/_A = 180 - 122
/_A = 58°
Hence,
/_A = 58°
/_B = 67°
/_C = 55°
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