Question

In ∆ABC, if angle b = 105°, angle C = 50°, then angle A=

Answer 1

$\bf\underline{\underline{\green{SOLUTION:-}}}$

Question

• In ∆ABC, if angle b = 105°, angle C = 50°, then angle A=?

Answer

• ∠A= 25°

Given

• ∠B= 105°
• ∠C= 50°

To Calculate

• ∠A__?

Explanation

∠B= 105°( Given )

∠C= 50° ( Given )

∠A = ?

Let ∠A= x

☆ Sum of all angles of a triangle = 180°

∠A+∠B+∠C = 180

➺ x + 105° + 50° = 180

➺ x+155 = 180

➺ x= 180-155

➺ x= 25°

$\bf\underline{\underline{\green{HENCE:-}}}$

• ∠A= 25°

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Answer 2

$\sf\red{Question:}$

In ∆ABC, if angle b = 105°, angle C = 50°, then angle A.

$\sf\red{Given:} ABC~ is ~a ~ Triangle \\ \\ \sf B=105°~ and~C=50°$

$\sf\red{To~find:} Angle~A$

$\sf\red{Solution:}</p><p> \sf Angle ~sum ~property~of~Triangle= \\ \\ \sf A°+B°+C°=180° \\ \\ \sf A°+105°+50°=180°\\ \\ \sf A°= 180 -155 \\ \\ \sf \implies A°=25°$