Question

In ΔABC, if DE || BC, AD = x, DB = x – 2, AE = x + 2 and EC = x – 1, then value of x is
2 points
(a) 4
(b) 3
(c) 5
(d) 3.5​

Answer 1

Answer:

In Δ ABC, DE ∥ BC

∴

DB

AD

=

EC

AE

(By basic proportionality theorem)

⇒

x−2

x

=

x−1

x+2

⇒x(x−1)=(x+2)(x−2)

⇒x

2

−x=x

2

−4

⇒x=4.

Step-by-step explanation:

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