Question

in ∆ ABC , if <B=90⁰ and cot A=1 , then the value of cos C sin A- cos A sin C is
a) 0
b) 1
c) 2
d) -1 ​

Answer 1

Answer:

b) 1

Step-by-step explanation:

Given,

in △ ABC, ∠B=90°

This given A+C=180° −90° =90°.....(1).

Now,

sinA.cosC+cosA.sinC

=sin(A+C)

=sin(90° )

=1

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