In ∆ABC if side AB =~ side AC,then_______.fill in the blanks
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In an isoceless triangle, The two sides and the two angles will be equal. The converse of the above theorem is.. "In a triangle ABC, if angle c =angle B, then the sides AB and AC are of equal length.
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Since AC>AB
So, ∠B>∠C
As angle opposite to the greater side is greater.
Now,
In △ADC and △ADB
∠ADC+∠C+∠DAC=180
∘
=∠ADB+∠B+∠DAB
Since ∠DAC=∠ADB
∠ADC+∠C=∠B+∠ADB
But, ∠B>∠C
So, to hold equality,
∠ADC>∠ADB
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