Question

In ABC, if sin A = 8/17, what is cos B?

Answer 1

Answer:

sinA=8/17

=sinA=p/h

=p=8;h=17

acc.to Pythagoras theorem

b=√(h^2-p^2)

b=√225=15

now ,

cosB=8/17

Answer 2

Hey

Given :-

Sin A = 8/17

Sin A = opposite / hypotenuse

so here ,

opposite side = 8

Hypotenuse side = 17

By pythagoreas theorem

hyp^2 = opp^2 + adj^2

adjacent side = 15

Therefore

Cos A = adjacent / hypotenuse

Cos A = 15/17

we know that

Sin A = Cos B and

Cos A = Sin B

Thus,

Cos B = 8/17