Question

In ∆ABC if tanA/2=5/6,tanB/2=20/37 then

Answer 1

Step-by-step explanation:

tanA/2=5/6 then 6tanA=5×2

tanA=5×2/6

=10/6

tanA=5/3

tanB/2=20/37 then 37 tanB=20×2

=20×2/37

tanB=40/37

tan A=5/3,tan B=40/37

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