In ∆ ABC,if3 angle A=4angleB=6angle C,calculate the angle
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2
in ∆ABC,
A =4° B= 6°
C= ?
IN ABC
A+B+C = 180°
4+6+C=180
10+C=180
C=180-10
C=170
A =4° B= 6°
C= ?
IN ABC
A+B+C = 180°
4+6+C=180
10+C=180
C=180-10
C=170
Answered by
1
✴ Now, as per Angle Sum Property Of Triangle,
✳ Angle A + Angle B + Angle C = 180°
✳ 4° + 6° + x° = 180°
✳ 10° + x° = 180°
✳ x° = 180° - 10°
✳ x° = 170°
✴ Therefore, Angle C = 170°
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