Question

In∆ABC ifa=2,b=3 and sinA=2/3 find angleB

Answer 1

Answer:

Answer:Explanation:Let ABC be a triangle with A = 3B and a ... [b(sqr(3))]^2 + b^2 = (2b)^2 => 3(b^2) + b^2 = (2b)^2 ...