Math, asked by rajegowdah, 5 months ago

In ∆ ABC, it angle A=x, B=x2 and C =3x then find the value of x

Answers

Answered by zahrathakur98
0

Step-by-step explanation:

ANSWER

Ina△ABC, (By angle sum property)

∠A+∠B+∠C=180∘

∠C−∠B=9

⟹y−(3x−2)=9

∴y=7+3x

x+(3x−2)+y=180∘

⟹4x−2+7+3x=180∘

⟹x=25∘

∴y=7+3×25=82∘

∴∠A=x=25∘,B=3x−2=73∘

∠C=y=82∘

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Answered by laasyanshu
0

Answer:

hey buddy, your answer is 30

Step-by-step explanation:

as we know that sum of interior angles of a triangle is 180°

now,

A+B+C = 180

substitute the values of A,B and C, we get

x+2x+3x = 180°

6x = 180°

x = 180÷6

x = 30

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