In ∆ ABC, it angle A=x, B=x2 and C =3x then find the value of x
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Answered by
0
Step-by-step explanation:
ANSWER
Ina△ABC, (By angle sum property)
∠A+∠B+∠C=180∘
∠C−∠B=9
⟹y−(3x−2)=9
∴y=7+3x
x+(3x−2)+y=180∘
⟹4x−2+7+3x=180∘
⟹x=25∘
∴y=7+3×25=82∘
∴∠A=x=25∘,B=3x−2=73∘
∠C=y=82∘
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Answered by
0
Answer:
hey buddy, your answer is 30
Step-by-step explanation:
as we know that sum of interior angles of a triangle is 180°
now,
A+B+C = 180
substitute the values of A,B and C, we get
x+2x+3x = 180°
6x = 180°
x = 180÷6
x = 30
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