In ∆ ABC it given that angle A = 65° and Angle B = 70°.Find angle C
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Answer:
Since, AB = AC, therefore, ∠B=∠C
By angle sum property of triangle,
∠A+∠B+∠C=180°
70°+2∠B=180°
2∠B=110°
∠B=55°
Hence, ∠B=∠C=55°
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