Question

In ∆ABC it is given that ∠A=70°,∠B=52° ,BO and CO are are the bisector of ∠B and ∠C respectively ,find ∠OCD and ∠BOC.​

Answer 1

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In ∆ABC it is given that ∠A=70°,∠B=52° ,BO and CO are are the bisector of ∠B and ∠C respectively ,find ∠OCD and ∠BOC.

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We have that the sum of the angles of a triangle is 180°.

$\therefore \: \angle \: A + \angle \: B + \angle \: C = 180\degree$

$⇒ 70\degree + 52\degree + \angle \: C = 180\degree$

$⇒ \angle \: C = (180\degree - 122\degree) = 58\degree$

$\therefore \: \angle \: OCB = \frac{1}{2} \angle \: C = ( \frac{1}{2} \times 58\degree) = 29\degree$

$and \: \angle \: OBC = \frac{1}{2} \angle \: B = ( \frac{1}{2} \times 52\degree) = 26\degree$

In ∆BOC,we have

$\angle \: OBC + \angle \: OCB + \angle \: BOC = 180\degree$

$⇒ 26\degree + 29\degree + \angle \: BOC = 180\degree$

$⇒ \angle \: BOC = (180\degree - 55\degree) = 125\degree$

$hence, \: \angle \: OCB = 29\degree \: and \: \angle \: BOC = 125\degree$

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Answer 2

Answer:

jo upar wala h wahi likh do bhaiya sahi answer dete h xD