Math, asked by RedBork, 19 days ago

In ∆ABC it is given that, AB/AC = BD/DC if Angle B=60° and Angle C = 60° , then Angle BAD is equal to
a) 30°
b) 40°
c) 45°
d) 50°

Explanation needed
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Answers

Answered by Anonymous
7

Answer:

Option (a) 30° is the correct answer.

Step-by-step explanation:

Given, in ∆ABC , AB/AC = BD/DC

Angle B = 60° and Angle C = 60°

We know that sum of angles of a triangle is 180°

In ∆ABC, Angle A + Angle B + Angle C = 180°

  • Angle A + 60° + 60° = 180°
  • Angle A = 180° - 120° = 60°

Now, AB/AC = BD/DC

Therefore, AD bisects BC.

(By angle bisector theorem)

Then, Angle BAC = 1/2 angle A = 30°

Hence, the value of Angle BAD is 30°

hope it helps you.

Answered by kiranbhanot639
3

Answer:

a) 30°.

A + B + C = 180o.

A = 180 - 70 - 50 = 60o.

BAD = 60/2 = 30o.

thanks

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