In ∆ABC it is given that, AB/AC = BD/DC if Angle B=60° and Angle C = 60° , then Angle BAD is equal to
a) 30°
b) 40°
c) 45°
d) 50°
Explanation needed
No Spam
Answers
Answered by
7
Answer:
Option (a) 30° is the correct answer.
Step-by-step explanation:
Given, in ∆ABC , AB/AC = BD/DC
Angle B = 60° and Angle C = 60°
We know that sum of angles of a triangle is 180°
In ∆ABC, Angle A + Angle B + Angle C = 180°
- Angle A + 60° + 60° = 180°
- Angle A = 180° - 120° = 60°
Now, AB/AC = BD/DC
Therefore, AD bisects BC.
(By angle bisector theorem)
Then, Angle BAC = 1/2 angle A = 30°
Hence, the value of Angle BAD is 30°
hope it helps you.
Answered by
3
Answer:
a) 30°.
A + B + C = 180o.
A = 180 - 70 - 50 = 60o.
BAD = 60/2 = 30o.
Similar questions