Question

In ABC it is given that AB/AC=BD/DC if angleB=70 and angleC=50 then angleBAD=?​

Answer 1

${\huge{\mathfrak{{{\purple{\fbox{\pink{Answer}}}}}}}}$

${{{\underline{\mathfrak{{given:-}}}}}}$

Angle B = 70°

Angle C = 50°

${{{\underline{\mathfrak{{to \: find:-}}}}}}$

Angle A

${{{\underline{\mathfrak{{solution:-}}}}}}$

Let angle A be x.

Angle B + Angle C + Angle x = 180° (Angle Sum Property)

70 + 50 + x = 180°

120 + x = 180°

x = 180 - 120

x = 60°

${{{\underline{\mathfrak{{verification:-}}}}}}$

Angle B + Angle C + Angle A = 180°

70 + 50 + 60 = 180°

Therefore, Proved that x = 60°.

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❤️DimplePrincess❤️

Answer 2

${\huge{\mathfrak{{{{\fbox{\pink{Answer}}}}}}}}$

${{{\underline{\mathfrak{{given:-}}}}}}$

Angle B = 70°

Angle C = 50°

${{{\underline{\mathfrak{{to \: find:-}}}}}}$

Angle A

${{{\underline{\mathfrak{{solution:-}}}}}}$

Let angle A be x.

Angle B + Angle C + Angle x = 180° (Angle Sum Property)

70 + 50 + x = 180°

120 + x = 180°

x = 180 - 120

x = 60°

${{{\underline{\mathfrak{{verification:-}}}}}}$

Angle B + Angle C + Angle A = 180

70 + 50 + 60 = 180°

Therefore, Proved that x = 60°.

──────────────

Be brainly ♡~

❤️Inshaan69❤️