Question

in ∆ABC,L A=L C and BM bisects at L ABC. Prove that the BM is perpendicular to L AC


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Answer 1

Answer:

Step-by-step explanation:

In Δ ABM and Δ BCM

∠A=∠C

∠ABM=∠CBM ( BM is bisector of ∠B)

BM is common

Thus Δ ABM ≅ Δ BCM

So ∠BMA=∠BMC

also ∠BMA+∠BMC=180

so ∠BMA=∠BMC=90°

Thus BM is perpendicular to AC

Proved