In ABC<A=3, <B, <C=2 <B. find the three angles of triangle ABC
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Given,
<A = 3
<C = 2<B
Let <B be it only
Now,
<A + <B + <C = 180
3 + <B + 2<B = 180
3<B = 177
<B = 59
So,
<C = 2<B
= 2 (59)
= 118
<A = 3
<C = 2<B
Let <B be it only
Now,
<A + <B + <C = 180
3 + <B + 2<B = 180
3<B = 177
<B = 59
So,
<C = 2<B
= 2 (59)
= 118
iqra05:
this was helpful
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