In ΔABC < A= 450 , BC = 8 cm .O is the centre of
the circle
1, Find < BDC ?
2, Find < BCD ?
3, What is the length of BD ?
Answers
Answer:
Hey there !
Solution:
2x + y = 3
=> y = 3 - 2x
So let us get all the values,
If x = 1, y = ?
=> y = 3 - 2 ( 1 )
=> y = 3 - 2 = 1
Hence first Coordinate is ( 1,1 )
If x = 2, y = ?
=> y = 3 - 2 ( 2 )
=> y = 3 - 4
=> y = -1
Hence second coordinate is ( 2,-1 )
If x = 0, y = ?
=> y = 3 - 2 ( 0 )
=> y = 3 - 0
=> y = 3
Hence third coordinate is ( 0,3 )
Hence plotting these points on graph and joining them by a single straight line, we get,
Refer to the attachment for graph.
Hope my answer helped !
R
100
50°
5. In Fig. 12.21, the
bisectors of ZP
and ZQ meet at
a point 0. If ZR
= 100° and ZS
= 50°, find ZPOQ
PAbout
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Noble gases have a completely filled outermost shell and that’s why they are least reactive. Other element’s reactivity depends upon their ability to attain the noble gas configuration. In this section, we shall learn more about the valency of an atom.
Valence Electrons
If the outermost shell has 8 electrons then the element is said to have a complete octet. By gaining, sharing and losing the electrons the atoms complete their outermost orbital and make an octet.
The capacity of an atom is described by the total number of electrons lost, gained or shared to complete its octet and it also determines the valency of the atom.R
100
50°
5. In Fig. 12.21, the
bisectors of ZP
and ZQ meet at
a point 0. If ZR
= 100° and ZS
= 50°, find ZPOQ
P
△ABC is an equilateral triangle.
∠BAE=60
ABEC is a cyclic quadrilateral.
We know,
∠BAC+∠BEC=180
=>∠BEC=180−60
=120
We know that the angles subtended by an arc on the circumference on the same side are equal.
Therefore,
∠ABC=∠BDC
=>∠BDC=60
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