In ΔABC, <ABC = 90°, AB=8cm and bc=6cm. The length of the altitude from B on AC is
a-2cm
b-4.8cm
c-10cm
d-14cm
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1
Answer:
4.8 cm
Step-by-step explanation:
<ABC = 90°,
Thus ar( ΔABC)=1/2*AB*BC
=8*6/2=24 cm²
Now as per figure let the altitude from B to Ac=x
Then ar( ΔABC)=1/2*x*AC=24 cm²..............(1)
Now in AC²=AB²+BC²=64+36=100
So AC=10
From(1)
1/2*x*10=24
x=48/10-4.8 cm
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