Math, asked by sundaskavyanjali299, 5 hours ago

In ΔABC, <ABC=90° and BO is parallel to AC. If AB=5.7cm, BO=3.8cm, CD=5.4cm. What is the length of BC?
a. 7.8 cm
b. 8.7 cm
c. 8 cm
d. 8.1 cm​

Answers

Answered by Anonymous
41

Triangles

The following is the concept and tips that will be used to find the solution:

  • Corresponding angles are cingurent and corresponding sides of similar triangle are proportional.

We've been given that, In right ΔABC, ∠ABC = 90° and BO is parallel to AC. With this information, we've been asked to find out the length of BC if AB = 5.7cm, BO = 3.8cm, CD = 5.4cm.

In right ∆ABC and ∆BDC, we have;

  • ∠ABC = ∠BDC [Each 90°]
  • ∠BCA = ∠BCD [Common angles]

By AA similarity theorem, we get:

  • ∆ABC ~ ∆BDC [AA similarity]

We know that, corresponding sides of similar triangle are proportional. So,

 \implies \dfrac{AB}{BD} =  \dfrac{BC}{CD} \\  \\ \implies \dfrac{5.7}{3.8} =  \dfrac{BC}{5.4} \\  \\  \implies 1.5 = \dfrac{BC}{5.4} \\  \\  \implies BC = 1.5 \times 5.4 \\  \\  \implies \boxed{ \bf{BC = 8.1}}

Hence, the length of BC is 8.1cm. So, option (d) 8.1cm is correct.

\rule{90mm}{2pt}

MORE TO KNOW

SSS theorem : SSS similarity theorem states that, If the three sides of one triangle are equal to the three sides of another triangle, the triangles are congruent.

SAS theorem : SAS similarity theorem states that, if the two sides and the angle between those two sides are equal to another triangle, the triangles are congruent.

AAA theorem : AAA similarity theorem states that, If the three angles of one triangle are equal to the three angles of another triangle, the triangles are congruent.

AA theorem : AA similarity theorem states that, If two angles of one triangle are equal to the two angles of another triangle, then the triangles are similar.

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Answered by Rudranil420
34

Answer:

Correct Question :-

✯ In ΔABC, <ABC=90° and BO is parallel to AC. If AB=5.7cm, BD =3.8cm, CD=5.4cm. What is the length of BC?

Options :

  • ☯ a. 7.8 cm
  • ☯ b. 8.7 cm
  • ☯ c. 8 cm
  • ☯ d. 8.1 cm

Given :

✯ In ΔABC, <ABC=90° and BO is parallel to AC. If AB=5.7cm, BD =3.8cm, CD=5.4cm.

Find Out :-

✯ What is the length of BC?

Solution :-

Firstly, we have to show that △ABC ~△BDC

⦿ Let △ABC and △BDC

⦿ ∠ABC = ∠BDC [each 90°]

⦿ ∠ACB = ∠BCD [common angle]

∴ △ABC ~ △BDC [by AA similarity criterion]

Since, triangles are similar, hence corresponding sides are proportional.

We have :

  • AB = 5.7cm,
  • BD = 3.8cm,
  • CD = 5.4cm

So, according to the question or ATQ :-

\sf \longrightarrow \sf \dfrac{AB}{BC} =\: \dfrac{BD}{DC}

\sf \longrightarrow \sf \dfrac{5.7}{BC} =\: \dfrac{3.8}{5.4}

\sf \longrightarrow \sf BC =\: \dfrac{5.7 \times 5.4}{3.8}

\sf \longrightarrow \sf BC =\: \dfrac{30.78}{3.8}

\longrightarrow {\small{\bold{\purple{\underline{BC =\: 8.1\: cm}}}}}

Henceforth, the length of BC is 8.1 cm.

\purple{\rule{45pt}{7pt}}\red{\rule{45pt}{7pt}}\pink{\rule{45pt}{7pt}}\blue{\rule{45pt}{7pt}}

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