In ΔABC, m angle A =90,(AB)=7cm, (AC)=24cm then (CB)
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It's a right angle traingle
So according to Pythagoras theorem states that "In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides"
so (AB)^2+(AC)^2=(CB)^2
(24)^2+(7)^2=(CB)^2
576+49=(CB)^2
625=(CB)^2
CB= √625
CB=25 cm
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