Question

In ∆ABC,m angle B=90,A circle touches all the sides of ∆ABC.If AB =5,BC=12,find the radius of the circle with the formula of incircle that is a+b-c/2 plzzz do it fast

Answer 1

Here AC is the diameter of the circle.So since angle B = 90°

Therefore, by Pythagoras theorem:

AC² = AB²+BC²

AC² = 5² + 12²

AC² = 25 +144

AC² = 169

SO,AC = 13 cm

Now putting the formula:

a+b-c/2 = (5+12-13)/2

= 4/2 = 2 cm