In ΔABC, m∠C=90 and m∠A=m∠B,Is cosA=cosB?
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Hey there !
Solution:
So we know that in a triangle, the angle sum property of a triangle is 180°.
So it is given that, ∠ A = ∠ B and ∠ C == 90°
So let us take ∠ A to be x
So Applying Angle sum property, we get,
=> ∠ A + ∠ B + ∠ C = 180°
=> X + X + 90 = 180°
=> 2 X = 180 - 90
=> 2 X = 90
=> X = 90 / 2 = 45°
Hence the measure of A and B is 45° as ∠ A = ∠ B.
So we know that Cos 45 = 1 / √2
Hence Cos A = Cos B is true.
Hope my answer helped !
Answered by
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In ∆ABC ,
m<C = 90° ,
and m<A = m<B = x
m<A + m<B + m<C = 180°
[ Angle sum property ]
x + x + 90° = 180°
=> 2x = 180° - 90°
=> 2x = 90°
=> x = 90°/2
=> x = 45°
Therefore ,
m<A = m<B = 45°
Now ,
Cos A = cos45° = 1/√2 ---( 1 )
Cos B = cos 45° = 1/√2 ---( 2 )
from ( 1 ) and ( 2 ), we get
Cos A = cos B
••••
m<C = 90° ,
and m<A = m<B = x
m<A + m<B + m<C = 180°
[ Angle sum property ]
x + x + 90° = 180°
=> 2x = 180° - 90°
=> 2x = 90°
=> x = 90°/2
=> x = 45°
Therefore ,
m<A = m<B = 45°
Now ,
Cos A = cos45° = 1/√2 ---( 1 )
Cos B = cos 45° = 1/√2 ---( 2 )
from ( 1 ) and ( 2 ), we get
Cos A = cos B
••••
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