Question

in ΔABC, m<B=90°,where BD is perpendicular to AC. if AB =9cm, AC=2.5cm. find BD=?
​

Answer 1

Answer:

Given:

∠BDC=90

∘

∠ABC=90

∘

Let ∠BCD=x

∘

Using triangle sum property in △BDC, ∠DBC=90−x

∘

Also ∠ABD=x

∘

Using triangle sum property in △ADB, ∠BAD=90−x

∘

Now considering △BDC and △ADB

∠BDC=∠BDA

∠BCD=∠ABD

∠DBC=∠DAB

So by AAA

△BDC∼△ADB

Hence

CD

BC

=

BD

AB

5.4

BC

=

3.8

5.7

BC=8.1

Hence BC=8.1cm

Answer 2

Answer:

the correct ans is BD=8.91