In Δ ABC, mC = 3 mB = 2 (mA + mB). Then find the measures of all three angles.
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Step-by-step explanation:
mC = 3mB. => C = 3B
3mB = 2mA + 2mB => A = 0.5B
in a triangle, A+B+C=180
0.5B+B+3B=180
4.5B=180
B=40
A=0.5x40=20
C=3x40=120
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