Question

In Δ ABC, mC = 3 mB = 2 (mA + mB). Then find the measures of all three angles.

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Answer 1

Hope it's helpful dear.............

Answer 2

Answer:

given

C = 3B

3B = 2(A + B)

3B = 2A + 2B

2A = B

A = B/2

now

A + B + C = 180

B/2 + B + 3B = 180

(B + 2B + 6B) /2 = 180

9B/2 = 180

B = 180*2/9

= 360/9

B = 40°

A = B/2

= 40/2

A = 20°

C = 3B

= 3*40°

= 120°

thus, angles are 20°, 40° , and 120°