in ∆ ABC measure of angle A= X° , measure of angle b =3x°, measure of angle C = y° and 3Y - 5x is equal to 30. find the measure of all angles of ∆ ABC hence prove that ∆ ABC is a right angled triangle
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we know that sum of all the angles of a triangle is 180
so
A + B+ C = 180
X + 3X + Y = 180
4x + y = 180-------------1 eq
now we have given
3y - 5x = 30
so y = 30 +5x/3 ---------------------2 eq
substituting value of y in eq 1
4x + 30 + 5x/ 3 = 180
taking lcm to get
12x +30 + 5x / 3 = 180
12x+ 30 + 5x = 180 * 3
17x + 30 = 540
17x = 510
x = 30
substituting value of x in equation 2
3y - 5x = 30
3y - 150 = 30
y = 180/3
y = 60
so a = 30 c = 60 and B = 3*30 = 90
hence it is a right angled triangle
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