Question

In ∆ABC measurements of the angle A= 90°, AB = 20cm, AC = 21cm. Find the value of sin B+CosC.

Answer 1

Hii... Pepsi____❤️

Answer-:

Let AB(p) = 20cm

AC(h)= 21cm

Then BC= √(AB)^2+ (AC)^2

=> √20^2 + 21^2

=> √400+ 441

=> √841

=> 29 cm

Now,

Sin B= AC/BC= 21/29

Cos C= AC/BC= 21/29

Find out Sin B+ Cos C

=> 21/29+21/29

=> 21+21/29

=> 42/29

Hope it help uh!! Pepsi❤️

Be brainly......☺️

Answer 2

AB=20 AC=21 THEN BC=
$\sqrt{20 {}^{2} +21 {}^{2} }$
=
$\sqrt{841}$
sinB+cosC = 21/(841)^1/2+21/(841)^1/2

=
42/29