in ∆ABC MN||BC AM=6 BM=9 AN=8 find CN
Answers
Answer:
in ∆ABC MN||BC AM=6 BM=9 AN=8, then CN = 12.
Step-by-step explanation:
Given: In ΔABC, MN || BC, AM = 6, BM = 9, AN = 8
Find CN
Steps: In ΔABC, MN || BC (Given)
AM/MB = AN/NC
6/9 = 8/CN
6CN = 9 × 8
6 CN= 72
CN= 72/6
CN= 12
Answer:
The value of CN is 12.
Step-by-step explanation:
As per the data given in the question we have to find CN. As per the questions it is given that In ΔABC, MN || BC, AM = 6, BM = 9, AN = 8
According to given figure MN parallel to BC and
AB=AC ( sides opposite to equal angle are equal )
In ∆ABC , M and N are points on the sides AB and AC respectively such that BM= CN.
AM/MB = AN/NC
Putting the value of AM,BM,AN we get
= 6/9 = 8/CN
= 6*CN = 9 × 8
= 6*CN= 72
= CN= 72/6
= CN = 12
Two triangle AMN and triangle ABC are similar (Angle,Angle,Angle)
MN/BC = AM/AB
Hence, the value of CN is 12.
For such type of questions:
https://brainly.in/question/49588884
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