Math, asked by tanvir7512, 8 months ago

In abc o is the mid point of bc

Answers

Answered by Anonymous
7

Step-by-step explanation:

if o is the mid point it will form two triangles of 90°at o point

by theorem we get

oa^2+ob^2=ab^2 (1)

&

oa^2+oc^2=ac^2 (2)

by adding (1)&(2) we get

oa^2+ob^2+oa^2+oc^2=ab^2+ac^2

2oa^2+ob^2+oc^2=ab^2+ac^2

ob=oc so

2 (ob^2+oc^2)=ab^2+bc^2

Answered by Anonymous
2

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A line through P and parallel to CA meets AB at point Q; and a line through Q meets at S. QS parallel to BC meets median AP at point R.

prove that :

(i) AP = 2AR

(ii) BC= 4QR

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