In abc o is the mid point of bc
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Answered by
7
Step-by-step explanation:
if o is the mid point it will form two triangles of 90°at o point
by theorem we get
oa^2+ob^2=ab^2 (1)
&
oa^2+oc^2=ac^2 (2)
by adding (1)&(2) we get
oa^2+ob^2+oa^2+oc^2=ab^2+ac^2
2oa^2+ob^2+oc^2=ab^2+ac^2
ob=oc so
2 (ob^2+oc^2)=ab^2+bc^2
Answered by
2
A line through P and parallel to CA meets AB at point Q; and a line through Q meets at S. QS parallel to BC meets median AP at point R.
prove that :
(i) AP = 2AR
(ii) BC= 4QR
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