in ∆ABC,P and Q are two points on AB and AC respectively such that PQ||BC and AP/PB=2/3,then find AQ/AC
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Since PQ is parallel to BC, ∆APQ is similar to ∆ABC.
Further PQ divides the ∆ABC inti two parts of equal areas ∆ABC / ∆APQ = 2/1
But ∆ABC/∆APQ = (AB/AP)^2 = 2/1
=> AB/AP = √2/1 => AB/(AB-AP) = √2/(√2–1)
=> AB/BP = √2/(√2–1) => BP/AB = (√2 - 1)/√2
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