In Δ ABC (picture attached), the point D lies on the AC side and E on the BC side. We also know ∡ABD = 30°, ∡BAE = 60°, ∡CAE = 20°, ∡CBD = 30°. Can you please calculate ∡AED = ? °
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Given: △s ABD and CAE are equilateral triangles.
∠CAD=∠CAB+∠BAD
∠CAD=∠CAB+60 (I)
∠BAE=∠BAC+∠CAD
∠BAE=∠BAC+60 (II)
Thus, from I and II
∠CAD=∠BAE (∠BAC=∠CAB (Common angles))
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