IN ∆ ABC point D is on side BC such that BD=3 BC =5 find A(∆ABD)/A(∆ABC)
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Answer:
3/5
Step-by-step explanation:
Given : point D is on side BC such that BD=3 BC =5
To find : A(∆ABD)/A(∆ABC)
Solution:
Let draw AM ⊥ BC
As D is a point on BC
Hence AM ⊥ BD also
Area of Δ = (1/2) * Base * Height
Area of Δ ABC = (1/2) * BC * AM
Area of Δ ABD = (1/2) * BD * AM
Area of Δ ABD / Area of Δ ABC = ((1/2) * BD * AM) / ( (1/2) * BC * AM)
=> Area of Δ ABD / Area of Δ ABC = BD/BC
=> Area of Δ ABD / Area of Δ ABC = 3/5
A(∆ABD)/A(∆ABC) = 3/5
I hope this helps ✌️
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