Question

In ∆ ABC point D is on side BC such that DC = 6 , BC =15 . find A(∆ABC) : A(∆ADC).
Pls send Detailed answer.
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Answer 1

Answer:

Step-by-step explanation:

ΔABC, ΔABD, ΔADC all have same height 'h'.

Base length of ΔABC = 15

Base length of ΔABD = 9

Base length of ΔADC = 6

Area of ΔABC= 1/2 × h ×15

Area of ΔABD= 1/2 × h ×9

Area of ΔADC= 1/2 × h ×6

A(ΔABD) : A(ΔABC) = (1/2 × h ×9):(1/2 × h ×15) = 3:5

A(ΔABD) : A(ΔADC) = (1/2 × h ×9):(1/2 × h ×6) = 3:2

Answer 2

Step-by-step explanation:

In ∆ ABC point D is on side BC such that DC = 6 , BC =15 .

A(∆ABD) : A(∆ADC) =3/2

A(ABD):A(AABC)=3/5